# One-third of an air tank is removed with each stroke of a vacuum pump. What part of the original amount of air remains after 5 strikes?

##### 1 Answer
Dec 21, 2015

Part remaining after n strikes $= {\left(1 - \frac{1}{3}\right)}^{n}$

#### Explanation:

Part remaining after 5 strikes $= {\left(1 - \frac{1}{3}\right)}^{5} = \frac{32}{243}$

~~13.17% remaining

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