Question

Or church committee has three liberals and five conservatives. if a committee of three people is the selected. find probability of one liberals and two conservative?

Answer 1

`= 15/28`

Explanation:

There are `((8),(3)) = 56` ways of choosing 3 people randomly from this population.

And then...

• There are `((3),(1))= 3` ways of choosing a liberal randomly from 3 liberals.

• There are `((5),(2))= 10` ways of choosing a 2 conservatives randomly from 5 conservatives.

So the probability of one liberal and two conservative is:

`(((3),(1)) times ((5),(2)))/(((8),(3))) = 15/28 approx 0.54`