# Organic Chem: The transformation shown here can be achieved via a two-step synthesis. Draw the product of the first step of this synthesis?

Feb 14, 2018

Well, first we would probably brominate the methyl group....

#### Explanation:

And so....

${C}_{6} {H}_{5} C {H}_{3} \stackrel{N B S , h \nu}{\rightarrow} {C}_{6} {H}_{5} C {H}_{2} B r + H B r$

And then the benzyl bromide would be treated with a cyanide nucleophile....

C_6H_5CH_2Br +K^(+)""^(-):C-=N rarrC_6H_5CH_2C-=N+KBrdarr