Question

Osmotic pressure of a solution containing 1g protein in 100 mL solution at 300K is 1.66 bar.What is the molecular weight of protein?

Answer 1

That's a pretty small protein! Its molecular wt. is approximately `150g` according to the subsequent calculations.

Explanation:

`Pi = iMRT`

`1.66b ar * (atm)/(1.013b ar) = 1 * M * (0.08206L*atm)/(mol*K) * 300K`

`M = 0.0666M`

Uh oh... that means this problem is from hell :(

`0.100L * (0.0666mol)/L = 1g * 1/(AW)`
`therefore AW approx 150g`