Oxidation number of the formula K2O5?

1 Answer
anor277
Apr 16, 2018

Is this known?

Explanation:

And ostensibly you got #K_2O_5#... And this is possibly #2xxK^+ + underbrace(5xxO)_"a -2 charge"#...I suppose we could formulate the peroxide anion as...#""^(-)O-O-O-O-O^(-)#...but I don't believe it.

I think possibly that you gots...#K_2O_2#. i.e. #"potassium peroxide"#, #K_2^(+)(""^(-)O-O^(-))#.

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