Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. To what temperature should it be raised to occupy a volume of 6.5 liters?

1 Answer

Answer:

884.5 K

Explanation:

1) Convert 40 °C to Kelvin and you get 273 + 40 = 313 K .At this temperature the volume of the gas is 2.3 L.

2) At Temperature #T_2# Kelvin ,this temperature the volume of the gas is 6.5 L.

Remember that you have to plug into the equation in a very specific way. The temperatures and volumes come in connected pairs and you must put them in the proper place.

Using Charles law equation;

#V_1# / #T_1# = #V_2# / #T_2#

#V_1# = 2.3 L , #T_1# = 313 K

#V_2# = 6.5 L , #T_2# = ?

plug in the values;

2.3 L / 313 K = 6.5 L / #T_2#

Cross-multiply and divide:

2.3 L x (#T_2#) = 6.5 L x 313 K

2.3 L x (#T_2#) = 2034.5 L K

#T_2# = 2034.5 LK / 2.3 L

#T_2# = 884.5 K