Part of the proceeds from a garage sale was $490 worth of $10 and $20 bills. lf there were 4 more $10 bills than $20 bills, how do you find the number of each denomination?

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Answer 1 · 2017-05-18T14:03:55

15 ($20 dollar bills) and 19 ($10 dollar bills).

If we let #x# be the number of $20 dollar bills then there are #x+4# $10 dollar bills.

The equation of the problem is:
#10(x+4)+20(x)=490#
#10x+40+20x=490#
#30x=450#
#x=15#

Then there are 15 $20 dollar bills and 19 $10 dollar bills.

Answer 2 · 2017-05-18T14:05:26

19 #$10# bills and 15 #$20# bills

Your equation:
#20*x + 10*(4+x)=490#

#20x+40+10x=490#

#30x=450#

#x=15#

(x indicates number of #$20 bills).

Since there are 4 more bills under #$10# category compared to the other, Your 10 dollar bills number is #=15+4=19#.