# Part of the proceeds from a garage sale was $490 worth of$10 and $20 bills. lf there were 4 more$10 bills than $20 bills, how do you find the number of each denomination? ##### 2 Answers May 18, 2017 15 ($20 dollar bills) and 19 ($10 dollar bills). #### Explanation: If we let $x$be the number of$20 dollar bills then there are $x + 4$ $10 dollar bills. The equation of the problem is: $10 \left(x + 4\right) + 20 \left(x\right) = 490$$10 x + 40 + 20 x = 490$$30 x = 450$$x = 15$Then there are 15$20 dollar bills and 19 $10 dollar bills. May 18, 2017 19 $10 bills and 15 $20 bills #### Explanation: Your equation: $20 \cdot x + 10 \cdot \left(4 + x\right) = 490$$20 x + 40 + 10 x = 490$$30 x = 450$$x = 15$(x indicates number of $20 bills).

Since there are 4 more bills under $10# category compared to the other, Your 10 dollar bills number is $= 15 + 4 = 19\$.