# People in Japan on average eat 3 ounces of fish per day. How many pounds of fish is this per week?

Jul 9, 2018

5.6875/1("pound")/("week") -> 5.6875" pounds per week"

#### Explanation:

$\textcolor{b r o w n}{\text{Did you know that you cam manipulate units of measurement}}$$\textcolor{b r o w n}{\text{the same way you can numbers}}$

First lets count this in ounces per week

We need ounces per week $\to \left(\text{ounces")/("week}\right)$

We have got: $\left(\text{ounces")/("day}\right)$ so we need to change this by replacing the unit of day with the unit of week.

$\left(\text{ounces")/(cancel("day"))xx(cancel("days"))/("week") = ("ounces")/("week}\right)$
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$\textcolor{b r o w n}{\text{We do the same thing with the numbers}}$

[13/1 ("ounces")/(cancel("day"))]xx[7/1 (cancel("days"))/("week")] = 91/1 ("ounces")/("week")" "..Eqn(1)
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$\textcolor{b r o w n}{\text{Converting this to pounds}}$

There are 16 ounces in 1 pound ->16/1 ("ounces")/("pound")" "..Eqn(2)

So to covert $\left(\text{ounces")/("week}\right)$ into $\left(\text{pounds")/("week}\right)$ we can turn $E q n \left(2\right)$ upside

down and multiply. Like this:

$\textcolor{w h i t e}{\text{d")Eqn(1)color(white)("dddd")xxcolor(white)("ddd}} \frac{1}{E q n \left(2\right)}$

 91/1 (cancel("ounces"))/("week")color(white)("d")xxcolor(white)("d")1/16 ("pounds")/(cancel("ounces")) color(white)("d")=color(white)("d")91/16 ("pound")/("week")

But we need 1 week. So divide both top and bottom by 16

$\frac{91 \div 16}{16 \div 16} \left(\text{pound")/("week") color(white)("dddd")=color(white)("dddd") 5.6875/1("pound")/("week}\right)$