Question

Period of conical pendulum?

Answer 1

See the explanation below

Explanation:

`a_r=v^2/r`

`r=Tsintheta`

`T=(2pir)/v`

`a_r=(2pir/T)^2*1/r=(4pi^2r)/T^2`

`mg=Tcostheta`

`mv^2/r=ma_r=Tsintheta`

`a_r=g tan theta`

`g(tan theta)=(4pi^2r)/T^2`

`g(tan theta)=(4pi^2lsintheta)/T^2`

`T^2=(4pi^2)(lcostheta)/g`

The period of a conical pendulum is

`T=2pisqrt((lcostheta)/g)`