pH of a solution in which #["H"^(+)] = 1.25 xx 10^(-12) "M"#?
1 Answer
Dec 5, 2017
See the answer below...
Explanation:
I think,you are new about
#pH# .It is formula that,
#color(red)(pH=-log_10[H^+]# Hence the
#color(red)(pH# of the solution is#=>color(red)(-log_10(1.25xx10^-12)=11.9)# Hope it helps....
Thank you...