pH of a solution in which #["H"^(+)] = 1.25 xx 10^(-12) "M"#?

1 Answer

See the answer below...

Explanation:

I think,you are new about #pH#.

It is formula that, #color(red)(pH=-log_10[H^+]#

Hence the #color(red)(pH# of the solution is #=>color(red)(-log_10(1.25xx10^-12)=11.9)#

Hope it helps....
Thank you...