# Phosphoric acid, H_3PO_4, is neutralized by magnesium hydroxide, Mg(OH)_2. How many moles of water will be produced from the neutralization of 0.24 mole of H3PO4?

$\text{Phosphoric acid}$ acts as a DIACID in aqueous solution........
${H}_{3} P {O}_{4} \left(a q\right) + M g {\left(O H\right)}_{2} \left(s\right) \rightarrow M {g}^{2 +} H P {O}_{4}^{-} \left(a q\right) + 2 {H}_{2} O \left(l\right)$.
Given the 1:1 stoichiometry (and 1:2 stoichiometry with respect to water, $0.48 \cdot m o l$ of water will be generated, i.e. approx. $9 \cdot g$.