Phosphoric acid, #H_3PO_4#, is neutralized by magnesium hydroxide, #Mg(OH)_2#. How many moles of water will be produced from the neutralization of 0.24 mole of H3PO4?

1 Answer
anor277
May 11, 2017

#"Phosphoric acid"# acts as a DIACID in aqueous solution........

Explanation:

And thus we write the stoichiometric equation:

#H_3PO_4(aq) + Mg(OH)_2(s) rarr Mg^(2+)HPO_4^(-)(aq) + 2H_2O(l)#.

Given the 1:1 stoichiometry (and 1:2 stoichiometry with respect to water, #0.48*mol# of water will be generated, i.e. approx. #9*g#.

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