Physics :- Motion in a straight line ....... HELP?

the distance traveled by a particle along a straight line is given by
s= 180 t+50 t ^2 find
the initial velocity of the particle
velocity at the end of 4 second
acceleration of the particle.

1 Answer
Jun 23, 2018

I tried this:

Explanation:

I would try deriving your expression to find the velocity and again to find the acceleration.

So we get:

(ds)/(dt)=v(t)=180+100t...........................................(1)

Initial velocity at t=0

v(0)=180m/s

At t=4:

v(4)=180+400=580m/s

For the acceleration (derive (1)):

(d(t))/(dt)=a(t)=100m/s^2