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1 Answer
Apr 18, 2018

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Angle subtended by the diameter of each of 2003 unit circles (or the distance between the centers of two adjacent unit circles) at the center of the circle of radius #r# will be #angle AOB=((2pi)/2003)#.

The length of the straight line #OA# joining the center #O# of the large circle of radius #r# with any of the center #A# of the unit circle of unit radius will be #OA=r+1# . The length of the straight line joining the point of contact #C#of two adjacent unit circle with the center of the large circle will be perpendicular to #AC#, the radius of the unit circle.

Hence in #Delta ACO, angle ACO=90^@#

Its hypotenuse #OA=r+1# and opposite #AC=1#

This right triangle will have an angle #angleAOC=pi/2003# at the center of the large circle.

For this right triangle we have #cosec(pi/2003)=(OA)/(AC)=(r+1)/1#

Hence #r=cosec(pi/2003)-1#