Question

Please help me ?

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Answer 1

`"E " f'(x) = 5/(3x^(2/3))`

Explanation:

Note that if `a != 0` then:

`d/(dx) x^a = a x^(a-1)`

So we find:

`d/(dx) 5x^(1/3) = 5 * (1/3) * x^(1/3 - 1) = 5/3x^(-2/3) = 5/(3x^(2/3))`