Question

Please help me with this logarithmic equation. How do I solve it?

Answer 1

`x=1`

Explanation:

`log(x(x+3))=log(x+1)^2` or

`x(x+3)=(x+1)^2` or

`x^2+3x=x^2+2x+1`

Solving for `x` we get

`x = 1`