Please solve q 10?

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Answer 1 · 2018-04-01T18:02:51

The answer is #=2#

#x=a/(b+c)#

#y=b/(c+a)#

#z=c/(a+b)#

Therefore,

#1/(1+x)=1/(1+a/(b+c))=(b+c)/(a+b+c)#

#1/(1+y)=1/(1+b/(c+a))=(c+a)/(a+b+c)#

#1/(1+z)=1/(1+c/(a+b))=(a+b)/(a+b+c)#

Finally,

#1/(1+x)+1/(1+y)+1/(1+z)#

#=(b+c)/(a+b+c)+(c+a)/(a+b+c)+(a+b)/(a+b+c)#

#=(b+c+c+a+a+b)/(a+b+c)#

#=(2(a+b+c))/(a+b+c)#

#=2#