Please solve q 31?

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Answer 1 · 2018-04-15T16:00:15

The answer is #"option (d)"#

#"Question (31)"#

Let

#a/(b+c)=k#, #=>#, #a=(b+c)k#

#b/(c+a)=k#, #=>#, #b=(a+c)k#

#c/(a+b)=k#, #=>#, #c=(a+b)k#

Therefore,

#(a+b+c)=(b+c)k+(a+c)k+(a+b)k#

#(a+b+c)=(bk+ck)+(ak+ck)+(ak+bk)#

#(a+b+c)=2k(a+b+c))#

#k=1/2#

Similarly if #k'=1/k#

#k'=2#

The answer is #"option (d)"#