Please solve the q 75?

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Answer 1 · 2018-05-02T16:33:16

The correct answer is #option (2)#

#"NTP "= 298.3 K " and " 760 " mm Hg"#

The equation of the decomposition of potassium chlorate is

#2KClO_3(s) rarr 2KCl(s)+3O_2(g)#

#1# mole of oxygen #(16g)# has a volume of #=24.45L " mole"^-1#

Therefore,

#11.2 L# correspond to #=11.2/24.45=0.46 " mole "#

#3# moles of oxygen is obtained from #2# moles of potassium chlorate

so,

#0.46# moles is obtained from #=2/3*0.46=0.31# mole of potassium chlorate