Please solve this question?

The number of natural numbers for which #(15n^2+8n+6)/n# is a natural number is?

1 Answer
Jan 7, 2018

#4#

Explanation:

#(15n^2+8n+6)/n in N#

#15n+8+6/n in N#

We have

#15n+8 in N# for all #n in N#

So we just need to find all #n# for #6/n in N#

In other words,

#n | 6#, or #n# is a factor of #6#, and #n in {1,2,3,6}# (because #6/n > 0#)

There are #4# values for #n# that satisfy the equation #(15n^2+8n+6)/n in N#.

Checking all solutions for #n#:

#n=1, (15n^2+8n+6)/n=29#

#n=2, (15n^2+8n+6)/n=41#

#n=3, (15n^2+8n+6)/n=55#

#n=6, (15n^2+8n+6)/n=99#