Preparation of 7M HCl in 100ml?

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Answer 1 · 2018-02-26T14:59:14

Well, first off, we must mention an issue of SAFETY ....

$"You add ACID to water and NEVER WATER to the acid."$

Why not?

$"Because if you spit in acid it spits back....I kid you not."$

The conc. hydrochloric acid bottle I have in front of me now claims...

$%34("m/m")$ , and $rho=1.169*g*mL^-1$ ...and thus we work out the $"molarity"="moles of solute"/"volume of solution"$

And so working from a $1*mL$ volume we gots....

$((34%xx1*mLxx1.169*g*mL^-1)/(36.46*g*mol^-1))/(1xx10^-3*L)=10.90*mol*L^-1$ ...

And since $C_1V_1=C_2V_2$

$V_1=(C_2V_2)/(C_1)=(7.0*mol*L^-1xx100*mL)/(10.90*mol*L^-1)=64.2*mL$ ...

...the which we add to $36*mL$ of water....(the solution will get hot!).

AGAIN YOU ADDS ACID TO WATER AND NEVER THE REVERSE. $"CLARO?"$