Prove It? Sin3θ/Sinθ-cos3θ/cosθ=2

1 Answer
Ananda Dasgupta
May 21, 2018

#sin(3theta)/sin(theta)-cos(3theta)/cos(theta)=(sin(3theta)cos(theta)-cos(3theta)sin(theta))/(sin(theta)cos(theta))#
#qquad=sin(3theta-theta)/(sin(theta)cos(theta))#
#qquad=sin(2theta)/(sin(theta)cos(theta))#
#qquad=(2sin(theta)cos(theta))/(sin(theta)cos(theta))=2#

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