Prove that ?

tan^2.sin^2 +cos^2+2sin^2=sec^2

1 Answer
Mar 2, 2018

Please see explanation section.
tan^2color(red)(x)sin^2color(red)(x)+cos^2color(red)(x)+2sin^2color(red)(x)=sec^2color(red)(x)

Explanation:

I think the Question is:
tan^2xsin^2x+cos^2x+2sin^2x=sec^2x
LHS=tan^2xsin^2x+cos^2x+2sin^2x=tan^2xsin^2x+color(red)(cos^2x+sin^2x)+sin^2x=tan^2xsin^2x+sin^2x+color(red)(1)
=sin^2xcolor(red)((tan^2x+1))+1
=sin^2x*color(red)(sec^2x)+1
=sin^2x/cos^2x+1
=tan^2x+1
=sec^2x
=RHS