Prove that lim_(n->oo) (2n+1)/(3n+2)=2/3 ?

1 Answer
Jim G.
Nov 2, 2017

#"see explanation"#

Explanation:

#(2n+1)/(3n+2)#

#"divide terms on numerator/denominator by n"#

#=((2n)/n+1/n)/((3n)/n+2/n)=(2+1/n)/(3+2/n)#

#rArrlim_(ntooo)(2n+1)/(3n+2)#

#=lim_(ntooo)(2+1/n)/(3+2/n)=(2+0)/(3+0)=2/3#

#"note that as "ntooo, 1/n" and "2/nto0#

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