Question is lengthy so I've attached the screenshot. Can you help? It's probability.

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1 Answer
Apr 19, 2018

84%

Explanation:

.

Let's assign a few parameters:

z= total number of students.

x= the number of students that got a score of 80/100 or higher on midterm 1.

y= the number of students that got a score of 80/100 or higher on midterm 2.

Now, we can say:

x/z=0.25, :. x=0.25z

y/z=0.21, :. y=0.21z

The percentage of the students who had a score of 80/100 or higher on midterm 1 also got a score of 80/100 or higher on midterm 2 is:

y/x=(0.21z)/(0.25z)=21/25=84/100=84%

84% of the students that scored 80/100 on midterm 1 also scored 80/100 or higher on midterm 2.