Question related to the angle of refraction?
1 Answer
There is no exit ray from the second piece or associated refractive angle because the Critical Angle for the interface has been exceeded.
Explanation:
Here we have a case of serial refractions. We need to calculate the angle of refraction in the top piece to find the angle of incidence for the second piece. Then we can calculate the angle of refraction from the second piece. Snells’ Law states that
where Θi ("theta i") = angle of incidence = 55
Θr ("theta r") = angle of refraction = Need both
-
FIRST PIECE
#1.00 * sin(55) = 1.91 * sin(Theta_(r1))#
#sin(Theta_(r1)) = (sin(55)) /1.91 #
#sin(Theta_(r1)) = 0.429#
#Theta_(r1) = 25.4# -
SECOND PIECE
#Theta_i = 90 – Theta_(r1) = 64.5#
#1.91 * sin(64.5) = 1.50 * sin(Theta_(r2))#
#sin(Theta_(r2)) = sin(64.5)*1.91/1.50 #
#sin(Theta_(r2)) = 0.903*1.91/1.50 #
#sin(Theta_(r2)) = 1.15#
In this case we have an internally reflected ray
So, there is no exit ray from the second piece or associated refractive angle.
The critical angle is the first angle for which the incident ray does not leave the first region, namely when the "refracted" angle is
In this example to find the critical angle, we set it at
Using Snell's Law,
https://www.math.ubc.ca/~cass/courses/m309-01a/chu/Fundamentals/snell.htm