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Answer 1 · 2018-01-02T01:39:07

#x=1.2# kg

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Let's have the weight of the jug be #x# and the weight of the marbles that fill half the jug be #y#

#x+y=2.6#

#x+2y=4#

We can solve for #y# from one equation and substitute it in the other to solve for #x#:

#y=2.6-x#

#x+2(2.6-x)=4#

#x+5.2-2x=4#

#-x=-1.2#

#x=1.2# kg