|-(r+q)|=|r+q| why? If we are removing - sign then mode should also be removed...I am confused?

2 Answers
Aug 26, 2017

#|-(r+q)|=|-1||r+q|=|r+q|#

Explanation:

#|-(r+q)|=|-1||r+q|=|r+q|#

or

#|-(r+q)|=r+q=|r+q|#

Positive Value in Mode is remain Positive.

Aug 26, 2017

#"see explanation"#

Explanation:

#"the "color(blue)"absolute value function"# returns a positive value for whatever is inside it.

#"it is a measure of the distance a value is from the origin."#

#rArr|4|=|-4|=4#

#"since both 4 and - 4 are 4 units from the origin"#

#"and distance is always positive"#

#color(blue)"by definition"#

#|x|={((x;x>=0),(-x;x<0))#

#rArr|4|=4" and "|-4|=-(-4)=4#

#"also" |x|=sqrt(x^2)#

#rArr|-4|=sqrt((-4)^2)=4#

#rArr|r+q|=|-(r+q)|#