Ramla is making a mix CD. She can fit 6 songs on the CD, but has 11 favorite songs to choose from. If the order of songs is important to Ramla, how many different arrangements of 6 songs can she put on her CD?

1 Answer
Jul 12, 2016

#color(blue)(11xx10xx9xx8xx7xx6)=color(blue)((11!)/(5!))=color(blue)(332640)#

Explanation:

Assuming there are no duplicates on her CD:
there are #color(green)(11)# choice for the first song;
and for each of these there are #color(green)(10)# choices for her second song;
and for each of these there are #color(green)(9)# choices for her third song;
and for each of these there are #color(green)(8)# choices for her fourth song;
and for each of these there are #color(green)(7)# choices for her fifth song;
and for each of these there are #color(green)(6)# choices for her sixth song.

This results in #color(green)(11xx10xx9xx8xx7xx6)# different arrangements.