Recurring decimal to fraction?

How do you write #0.9999# recurring as a fraction. I know how to do ones like:

#0.8dot(8)=8/9# and so on. using #1/9# #1/99# #1/90# etc. The problem is you can't do it with 9 repeating.

1 Answer
Jun 8, 2018

#0.bar9=1#

#0.bar8 = 8/9#

Explanation:

let:

#m=0.bar9#

#10m=9.bar9#

subtract the first equation from the second one:

#10m=9.bar9#
#underline("- "m=0.bar9)#
#" "9m=9#

#m=1#

The other problem:

let:

#m=0.bar8#

#10m=8.bar8#

subtract the first equation from the second one:

#10m=8.bar8#
#underline("- "m=0.bar8)#
#" "9m=8#

#m=8/9#