# Refer to the image below and also give explanation for your answer...?

Jan 4, 2017

Option A

#### Explanation:

In diagram 1.

Given $V = 3.0 V$, and $I = 0.5 A$,
Using Ohm's Law we get the resistance $R$ as

$R = \frac{V}{I}$
$\implies R = \frac{3.0}{0.5} = 6 \Omega$

In diagram 2.

The voltage remains same and there is no change in the position of voltmeter. As such $V = 3.0 V$

An identical resistor is added in parallel with the first resistor. The combined resistance ${R}_{c}$ can be found from the resistances in parallel equation

$\frac{1}{R} _ \text{total} = \frac{1}{R} _ 1 + \frac{1}{R} _ 2$
$\implies \frac{1}{R} _ c = \frac{1}{6} + \frac{1}{6}$
$\implies \frac{1}{R} _ c = \frac{1}{3}$
$\implies {R}_{c} = 3 \Omega$

New current is found using Ohm's Law

$I = \frac{V}{R}$
$\implies I = \frac{3.0}{3}$
$\implies I = 1 A$