Relate the rate of decomposition of #NO_2# to the rate of formation of #O_2# for the following reaction? #2NO_2(g)# #rarr# #2NO_(g)# + #O_2#

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Answer 1 · 2018-02-24T14:31:17

#"2NO"_2 -> "2NO" + "O"_2#

For above reaction

#"Rate" = -1/2d/dt["NO"_2] = +1/2d/dt["NO"] = +d/dt["O"_2]#

∴ From above equation

#-1/2d/dt["NO"_2] = +d/dt["O"_2]#

#-d/dt["NO"_2] = +2d/dt["O"_2]#

In other words,

#"Rate of decomposition of NO"_2 = 2 × "Rate of formation of O"_2#