Question

Relate the rate of decomposition of `NO_2` to the rate of formation of `O_2` for the following reaction? `2NO_2(g)` `rarr` `2NO_(g)` + `O_2`

Answer 1

`"2NO"_2 -> "2NO" + "O"_2`

For above reaction

`"Rate" = -1/2d/dt["NO"_2] = +1/2d/dt["NO"] = +d/dt["O"_2]`

∴ From above equation

`-1/2d/dt["NO"_2] = +d/dt["O"_2]`

`-d/dt["NO"_2] = +2d/dt["O"_2]`

In other words,

`"Rate of decomposition of NO"_2 = 2 × "Rate of formation of O"_2`