Represent √3+i in polar form?

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Answer 1 · 2017-10-21T12:19:27

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Tony B

Answer 2 · 2017-10-21T12:21:37

#sqrt(3) + i = 2(cos(pi/6) + isin(pi/6))#

Let #sqrt(3) + i = z#

Modulus of #z#:

#|z| = sqrt(sqrt(3)^2 + 1^2) = sqrt(4) = 2 = r#

Argument of #z#:

#arctan(1/sqrt(3)) = pi/6 = theta#

#z = r(cos(theta) + isin(theta)) = 2(cos(pi/6) + isin(pi/6))#