# Scandium-44 (""_21^44Sc) decays by emitting a positron. Which nuclide is the product of the decay?

May 26, 2017

The answer is ""_20^44Ca

#### Explanation:

Here is a reference for Positron Emission .

Here is the equation:

${\text{_21^44Sc rarr }}_{20}^{44} C a + {e}^{+} + {v}_{e}$