Question

Scandium-44 (`""_21^44Sc`) decays by emitting a positron. Which nuclide is the product of the decay?

Answer 1

The answer is `""_20^44Ca`

Explanation:

Here is a reference for Positron Emission .

Here is the equation:

`""_21^44Sc rarr ""_20^44Ca+e^+ + v_e`