Should I write #H_2SO_4# like a catalyst?
The nitrate ion can be identified by heating copper turnings along with concentrated sulphuric acid. Here sulfuric acid reacts with the nitrate ion to form nitric acid. Nitric acid then reacts with the copper turnings to form nitric oxide. So, does reaction equation look like this?
#Cu + 4 HNO_3 → Cu(NO_3)_2 + 2NO_2 +2H_2O#
If yes, should I write #H_2SO_4# like a catalyst?
The nitrate ion can be identified by heating copper turnings along with concentrated sulphuric acid. Here sulfuric acid reacts with the nitrate ion to form nitric acid. Nitric acid then reacts with the copper turnings to form nitric oxide. So, does reaction equation look like this?
If yes, should I write
1 Answer
Yes.
The
If
Your reaction is therefore:
#"Cu"(s) + 4"HNO"_3(l) stackrel("H"_2"SO"_4" ")(->) "Cu"("NO"_3)_2(aq) + 2"NO"_2(g) + 2"H"_2"O"(l)#
When we balance this from half-reactions we might have written:
#"Cu"(s) -> "Cu"^(2+)(aq) + cancel(2e^(-))#
#ul(2(cancel(e^(-)) + 2"H"^(+)(aq) + "NO"_3^(-)(aq) -> "NO"_2(g) + "H"_2"O"(l)))#
#"Cu"(s) + 4"H"^(+)(aq) + 2"NO"_3^(-)(aq) -> "Cu"^(2+)(aq) + 2"NO"_2(g) + 2"H"_2"O"(l)#
or
#ul("Cu"(s) + 4"H"^(+)(aq) + 4"NO"_3^(-)(aq) -> "Cu"^(2+)(aq) + 2"NO"_3^(-)(aq) + 2"NO"_2(g) + 2"H"_2"O"(l))#
#"Cu"(s) + 4"HNO"_3(l) -> "Cu"("NO"_3)_2(aq) + 2"NO"_2(g) + 2"H"_2"O"(l)#
Here we write