Show the mechanism of KOH and alcohol for forming double bond in an alkyl halide?
1 Answer
Mar 3, 2018
Here's what I get.
Explanation:
In a solution of alcoholic
The position of equilibrium lies to the left, so there is not much ethoxide ion present.
However, ethoxide is a much stronger base than hydroxide, so it is the favoured reactant.
The ethoxide attacks an α-hydrogen atom in an
The products are ethanol, an alkene, and a halide ion.