Side lengths of an right triangle are sqrtn, sqrt(n+1), and sqrt(n+2). How do you find n?
1 Answer
Mar 16, 2018
Explanation:
Pythagoras' theorem tells us that the sides of a right angled triangle with legs of length
c^2 = a^2 + b^2
So in our example, we require:
(sqrt(n+2))^2 = (sqrt(n))^2+(sqrt(n+1))^2
Assuming
n+2 = n+(n+1)
Subtracting
1 = n
So the only solution is