Simplify this index law question?

Question

#(2xy^3)^2/(7x^3) times(3x^5y^2)/(4y) #

1081 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-23T06:28:57

#= (3 x^4 y^(7)) /(7)#

#(2 x y^3)^2/(7 x^3) * (3 x^5 y^2)/(4 y)#

expand

#= (2^2 x^2 (y^3)^2 * (3 x^5 y^2)) /(7 x^3 * 4 y)#

#= (4* x^2 * y^6 * 3 * x^5* y^2) /(7 * x^3 * 4 * y)#

#= (12 * x^(2+ 5) * y^(6 + 2)) /(28 * x^3 * y)#

#= (12 * x^(7 - 3) * y^(8 - 1)) /(28)#

#= (3* x^4 * y^(7)) /(7)#

#= (3 x^4 y^(7)) /(7)#