given: #color(blue)(y-(-2)=6[x-(6)])#
The key point hear is that if the signs are the same then the answer for that part is positive. On the other hand, if the signs are different then the answer for that part is negative.
Consider the part #[x-(6)]#
As there is no sign in front of the 6 within the bracket we consider the (6) as (+6) giving:
#[x-(+6)]#
The signs are not the same so this is:
#[x-6]#
Putting it back together:
#color(blue)(y-(-2)=6[x-6])#
Consider the part #y-(-2)#
The signs are the same so this becomes:
#y+2#
Putting it all back together:
#color(blue)(y+2=6[x-6])#
Consider the part #6[x-6]#
Multiply everything inside the brackets by #(+6)#giving:
#6x-36#
Putting it all back together
#color(blue)(y+2=6x-36)#
To get the #y# on its own subtract #color(red)(2)# from BOTH sides
#color(green)(y+2=6x-36 color(white)("dddd") -> color(white)("dddd") y+ubrace(2color(red)(-2)) color(white)("d")= color(white)("d")6x-ubrace(36color(red)(-2)))#
#color(green)( color(white)("ddddddddddddddd.dddddddddddd")darr color(white)("dddddddddd")darr#
#color(green)(color(white)("dddddddddddddddd")->color(white)("dddd")ycolor(white)("d..")+0color(white)("dd.")=color(white)("d")6xcolor(white)(".")-38#
#color(white)()#
#color(white)("ddddddddddddd")bar( ul(| color(white)(2/2)y=6x-38color(white)(2/2)|))#
