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Sin^2 θ + 8 sin θ cos θ = cos^2 θ What is theta?

1 Answer
Feb 19, 2018

#Sin^2θ + 8 sin θ cos θ = cos^2θ #

#=>cos^2θ -sin^2theta- 4*2 sin θ cos θ = 0 #

#=>cos2θ - 4 sin2 θ= 0 #

#=>cos2θ = 4 sin2 θ#

#=>tan2theta=1/4#

#=>2theta=npi+tan^-1(1/4)" where "ninZZ#
#=>theta=(npi)/2+1/2tan^-1(1/4)" where "ninZZ#