Sin (alpha-540°) Explain and Answer The Value?

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Answer 1 · 2018-06-10T10:14:02

$-sin(alpha)$

Using
$sin(alpha-540^(circ))=sin(alpha)*cos(540^(circ))-cos(alpha)*sin(540^(circ))$
since

$cos(540^(circ))=-1$
$sin(540^(circ))=0$
we get

$-sin(alpha)$

Answer 2 · 2018-06-11T00:09:06

$-sin a$

$sin (a - 540) = sin (a - 180 - 360) = sin (a - 180) = - sin a$