(Sinx+cox)dx ?

1 Answer
May 19, 2018

#int(sinx+cosx)"d"x=sinx-cosx+C#

Explanation:

We have #I = int(sinx+cosx)"d"x#

By the linearity of the integral, we can rewrite it as:

#I = intsinx"d"x+intcosx"d"x#

These are standard integrals, and are assumed as known:

#int sinx"d"x=-cosx+C_1#
#int cosx"d"x=sinx+C_2#

#=> I = sinx-cosx+C_1+C_2#

Since the sum of two constants is still a constant, denoted #C# in our case, we have the answer we seeked:

#color(Red)(I = sinx-cosx+C)#