Six identical particles each of mass ‘m’ are arranged at the corners of a regular hexagon of side length ‘L’. If the masses of any two adjacent particles are doubled. The shift in the centre of mass is???
The center of mass of the original arrangement (six equal masses
The new arrangement (after two of the adjacent masses are doubled) is equivalent to the older one, with the addition of two masses equal to
As far as the center of mass is concerned, this is equivalent to a mass of
The shift in the center of mass is