Solve Sec^2x - 1 = 1/cot(x)? Interval of x is [0, 360)

sec^2x - 1 = 1 / cot(x)

1 Answer
May 28, 2018

x = 0 or 90

Explanation:

First, we use Pythagorean identities.

sec^2(x) - 1 = tan^2(x)

tan^2(x) = tan(x)

We now have a polynomial in tan(x).

tan^2(x) - tan(x) = 0

tan(x)(tan(x)-1) = 0

So, tan(x) = 0 or tan(x) = 1.

x = 0 or 90.