Solve the equation #3loga^x=loga^8# ?

Question

#3loga^x=loga^8#

the "a" on both sides is meant to be subscript and the "x" on both sides is meant to be written normally, however I couldn't find a way to express this in the question.

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Answer 1 · 2018-02-27T14:58:29

#x = 2#

#3log_ax = log_a8#

#log_ax^3 = log_a8#

After canceling log on both sides , you get

#x^3 = 8#

#x^3 = 2^3#

You can cancel the cubes

Therefore , #x =2#

Answer 2 · 2018-02-27T15:08:37

#x=2#

Given:

#3log_ax=log_a8#

#8=2^3#

#3log_ax=log_a2^3#

Using the power rule in logarithms

#log(a^m)=mloga#

#3log_ax=3log_a2#

#x=2#