Solve the following? #x^(1/x)=1.2#

1 Answer
Mar 24, 2018

Use Lambert #W# function...

Explanation:

Given:

#x^(1/x) = 1.2 = 6/5#

Raise both sides to the power #x# to get:

#x = (6/5)^x = e^(x ln(6/5))#

Multiply both sides by #e^(-x ln(6/5))# to get:

#x e^(-x ln(6/5)) = 1#

Multiply both sides by #-ln(6/5)# to get:

#-x ln(6/5) e^(-x ln(6/5)) = -ln(6/5)#

This is in the form:

#z e^z = c" "# with #z = -x ln(6/5)#

This has solutions given by the Lambert #W# function:

#-x ln(6/5) = W(-ln(6/5))#

So:

#x = -1/ln(6/5) W(-ln(6/5)) = 1/ln(5/6) W(ln(5/6))#

Actually the Lambert #W# function has multiple branches. The real solutions in this example are for #W_0# and #W_(-1)# giving:

#x = 1/ln(5/6) W_0(ln(5/6)) ~~ 1.2577345#

#x = 1/ln(5/6) W_(-1)(ln(5/6)) ~~ 14.767458#