Solve the logarithmic equation. Thanks?!!

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1 Answer
Mar 22, 2018

See process below

Explanation:

#ln(x-8)-ln(x+7)=ln(x-10)-ln(x+8)#. Using logarithmic rules we have

#ln((x-8)/(x+7))=ln((x-10)/(x+8))#

Because #ln# is an inyective function, the expresions which is apply are the same. Thus

#(x-8)/(x+7)=(x-10)/(x+8)#. Trasposing terms

#cancelx^2-64=(x+7)(x-10)=cancelx^2-10x+7x-70#. Thus we have

#3x=-6#. Finally #x=-2#