Solve the rationalize the denominator 1-√2/2-√2?

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Answer 1 · 2018-05-07T14:06:50

the answer
#(1-3sqrt2)/2#

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#(1-sqrt2)/2-sqrt2/1#

#(1-sqrt2)/2-(2*sqrt2)/(2*1)#

#[1-sqrt2-2sqrt2]/2#

#(1-3sqrt2)/2#

Answer 2 · 2018-05-07T14:15:17

#color(green)(=> -sqrt2 / 2 #

#(1 - sqrt2) / (2 - sqrt2)#

#=> ((1 - sqrt2) * (2 + sqrt2)) / ((2 - sqrt2) * (2 + sqrt2)), " Multiply and divide by : "(2 + sqrt2)#

#=> (2 - 2 sqrt2 + sqrt2 - 2) / (4 - 2)#

#color(green)(=> -sqrt2 / 2 #