# Solve: x^(-3) = 8 How do I solve for x?

The answer is$\frac{1}{2}$
${x}^{- 3} = 8$
so $\frac{1}{x} ^ 3 = 8$
${x}^{3} = \frac{1}{8}$
$x = \sqrt[3]{\frac{1}{8}} = \frac{1}{2}$