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1 Answer
1s2s2p
May 15, 2018

#"CH"_3"COOH"_text[(aq)]+"NaHCO"_3""_text[(s)]->"CH"_3"COONa"_text[(s)]+"H"_2"O"_text[(l)] + "CO"_2""_text[(g)]#

Explanation:

#"Acid" + "Hydrogen carbonate" -> "Salt" + "CO"_2 + "H"_2"O"#

In this case we have #"CH"_3"COOH"# and #"NaHCO"_3#

The salt formed is #"CH"_3"COONa"# since the acid donates a proton. This leaves us with #"H"^+# and #"HCO"_3""^-#, instead of forming #"H"_2"CO"_3#, they form #"H"_2"O"# and #"CO"_2#, giving a reaction of:
#"CH"_3"COOH"_text[(aq)]+"NaHCO"_3""_text[(s)]->"CH"_3"COONa"_text[(s)]+"H"_2"O"_text[(l)] + "CO"_2""_text[(g)]#

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