sqrt(25y^2+40y+16) =5y+4 Solve the equation?

1 Answer
Apr 6, 2017

It is proved that sqrt[(25y)^2+40y+16] = 5y+4

Explanation:

Squaring both sides, we get

sqrt(25y^2+40y+16) = sqrt[(5y)^2+2xx5yxx4+(4)^2

rArr [sqrt(5y+4)]^2 = 5y+4 proved